Re: [PD] How does vline~ work under the hood?

Hi, On Sat, Sep 26, 2015 at 10:08:16PM +, Jonathan Wilkes wrote: > Hi Frank,The [1, 0 50( message will almost always trigger different output > when fed to [line~] and [vline~].  The only exceptionis when the ramp ends > exactly on a block boundary--otherwise [line~] will stretch ... or

Re: [PD] Pd-list Digest, Vol 126, Issue 118

0900, i go bananas wrote: > > In that case, maybe an even simpler question: > > > > What is the difference between sending a [1, 0 50( message to vline as > > opposed to line ? > > There will only be a difference in how line~ and vline~ react to this > message > when the message was triggered by something wi

Re: [PD] How does vline~ work under the hood?

No problem.  This is a difficult part of the software to understand. -Jonathan On Sunday, September 27, 2015 9:16 PM, i go bananas wrote: My apologies for doubting you Jonathan.  The line object does indeed stretch to fill the whole block.

Re: [PD] How does vline~ work under the hood?

My apologies for doubting you Jonathan. The line object does indeed stretch to fill the whole block. ___ Pd-list@lists.iem.at mailing list UNSUBSCRIBE and account-management -> http://lists.puredata.info/listinfo/pd-list

Re: [PD] How does vline~ work under the hood?

The ramp segments themselves are pretty simple once they get going -- the entire thing is calculated at once, and then it's just a matter of adding the resulting constant increment until the target time has elapsed, or a new event supersedes the current ramp. This is less than the interpolation