The higher the number, the more lower bits will be 0, because the floating
point mantissa is too small to store them. It becomes more clear if you use
binary notation.
Am 26. Mai 2021, 10:39, um 10:39, ro...@dds.nl schrieb:
>ro...@dds.nl schreef op 25-05-2021 23:16:
>
>> hi,
>>
>> because of
ro...@dds.nl schreef op 25-05-2021 23:16:
> hi,
>
> because of the problems i had with calculations using floating point math,
>
> and following Roman's advice, i changed to integer math.
>
> however that's easier said then done.
>
> i'm running again into an unexpected limitation:
>
>
Le 25/05/2021 à 23:16, ro...@dds.nl a écrit :
hi,
because of the problems i had with calculations using floating point math,
and following Roman's advice, i changed to integer math.
however that's easier said then done.
i'm running again into an unexpected limitation:
32-bits can
hi,
because of the problems i had with calculations using floating point
math,
and following Roman's advice, i changed to integer math.
however that's easier said then done.
i'm running again into an unexpected limitation:
32-bits can represent signed integers upto 2.147...billion.
