BODY { font-family:Arial, Helvetica, sans-serif;font-size:12px;
}John, list

        Thank you so much for this excellent outline of the reason for the Y
graph of the semiosic triad. It's perfect.

        AND - I like your statement: "The point in the center is either the
name off a relation or the name of a variable.". And that is why I
refer to the 'sign' term as the name of either that mediating
relation and/or the name of the whole variable.

        And also - thanks for using the term 'relations' rather than just
'correlate'. Peirce himself used both. 

        Edwina
 On Tue 12/10/21 10:45 PM , "sowa @bestweb.net" s...@bestweb.net
sent:
 The difference between a trianglular graph and a Y graph can be seen
in the translation to some version of logic, either linear or graphic.
  If we label the three nodes a, b, and c, the triangle can be
represented by three dyadic relations:  R(a,b) & S(b,c)  & T(c,a).  
But the Y requires  an irreducible triadic connection:  R(a,b,c).  
Some people would object that a Y can be replaced by introducing a
new variable x, and using three dyadic relations:  R(x,a) & S(x,b) &
T(x,c).   But note what happened:  the new variable x now has a
triadic connection to the three relations R, S, T.   If you draw
those linear expressions as graphs, you will find that there is a Y
shaped graph with the variable x at the center instead of the
relation R at the center.  No mattter which choice of variables and
relations you choose, there is no way to eliminate a Y-shaped triad. 
The point in the center is either the name off a relation or the name
of a variable.    Conclusion:  The triangle is a degenerate triad
because it can be replaced by three dyads.  But the Y is a genuine
triad because no transformation can get rid of a triadic connection
in the graph.   John 
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