BODY { font-family:Arial, Helvetica, sans-serif;font-size:12px; }John, list
Thank you so much for this excellent outline of the reason for the Y graph of the semiosic triad. It's perfect. AND - I like your statement: "The point in the center is either the name off a relation or the name of a variable.". And that is why I refer to the 'sign' term as the name of either that mediating relation and/or the name of the whole variable. And also - thanks for using the term 'relations' rather than just 'correlate'. Peirce himself used both. Edwina On Tue 12/10/21 10:45 PM , "sowa @bestweb.net" s...@bestweb.net sent: The difference between a trianglular graph and a Y graph can be seen in the translation to some version of logic, either linear or graphic. If we label the three nodes a, b, and c, the triangle can be represented by three dyadic relations: R(a,b) & S(b,c) & T(c,a). But the Y requires an irreducible triadic connection: R(a,b,c). Some people would object that a Y can be replaced by introducing a new variable x, and using three dyadic relations: R(x,a) & S(x,b) & T(x,c). But note what happened: the new variable x now has a triadic connection to the three relations R, S, T. If you draw those linear expressions as graphs, you will find that there is a Y shaped graph with the variable x at the center instead of the relation R at the center. No mattter which choice of variables and relations you choose, there is no way to eliminate a Y-shaped triad. The point in the center is either the name off a relation or the name of a variable. Conclusion: The triangle is a degenerate triad because it can be replaced by three dyads. But the Y is a genuine triad because no transformation can get rid of a triadic connection in the graph. John
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