> But I see that you may have a misconception about what enqueue adds and
> dequeue(_nb) removes. "enqueue" packages up _all_ of the parameters into a
> single "package" in the queue, which is returned as one set of parameters
> by "dequeue(_nb)". Try this:
>
> while ( my( $one, $two ) = $q->dequ
At 10:07 PM 10/28/02 -1000, Joshua Hoblitt wrote:
> Could you give me an example which gives you the error? I'd be
surprised...
--
use strict;
use Thread::Queue::Any;
my $q = Thread::Queue::Any->new();
$q->enqueue( [ 1, 2 ], [ 3, 4 ] );
while ( my( $one, $two ) = @{ ($q->dequeue_nb)[0] } ) {
> Could you give me an example which gives you the error? I'd be surprised...
--
use strict;
use Thread::Queue::Any;
my $q = Thread::Queue::Any->new();
$q->enqueue( [ 1, 2 ], [ 3, 4 ] );
while ( my( $one, $two ) = @{ ($q->dequeue_nb)[0] } ) {
print "$one, $two\n";
}
--
Can't use an u
At 11:14 AM 10/28/02 -1000, Joshua Hoblitt wrote:
> That's exactly the problem: the @{} is forcing scalar context, so that it
> tries to deref the value 1 always (which you'll see if you're using
strict).
I understand now... is there a pretty way to force the calling context?
Using (...)[0] is c
> That's exactly the problem: the @{} is forcing scalar context, so that it
> tries to deref the value 1 always (which you'll see if you're using strict).
I understand now... is there a pretty way to force the calling context? Using (...)[0]
is causing errors for me.
-J
