Type LOGOFF at the command prompt. You can lowercase commands and
abbreviate most
as well hence:
$ lo
will generally get you off. N.B. that "exit" will simply stop whatever
procedure or program that
you ^Y'ed out of. It won't get you off of the machine. "lo" will under
most circumstance
'user1' looks like a volume logical name not a physical device name.
configure.com ought to have f$parse()ed out the physical device name.
Peter Prymmer
"Craig A
At 11:56 AM 11/7/2001 -1000, Tim Jenness wrote:
>> not ok 28 # POSIX::errno(): 20, $!: 0
>>
>> which I think means autoloading sets errno but isn't supposed to. I suspect
>> it's doing a -d somewhere and leaving an errno of ENOTDIR laying about. Hmm.
>>
>
>Well, $! is meant to be exactly er
At 09:53 PM 11/7/2001 +0100, Tels wrote:
>So, if I read Tim correctly, make that my $foo = $! + 0; and it might
>pass the test. Needs probably a bit more munging to print the $! in
>numeric context as well as $foo after a failure.
Thanks Tels and Tim. With the following additional change:
---
> - my $foo = $!;
> + my $foo = 0 + $!; # force numeric
> my $errno = POSIX::errno();
> print "not " unless $errno == $foo;
> - print "ok ", 28 + $test, " # POSIX::errno(): $errno, \$!: $!\n";
> + print "ok ", 28 + $test, " # POSIX::errno(): $errno, \$!:
>From the command line:
$ show logical PERLSHR
as well as:
$ show logical PERL_ROOT
will be the (rough) equivalents of:
% echo $PATH
on Unix - at least as far as PERL is concerned. Craig's suggestion of
re-defining your PERL_ROOT to
point to your build directory is well worth following in
Do not bother trying to redefine the perlshr logical name. The only one
that
you need to redefine is PERL_ROOT since PERLSHR is defined in terms of
PERL_ROOT.
Try this:
$ @perl_setup
$ show default
$ show logical PERL_ROOT
$ define/trans=conc PERL_ROOT :[.]
Where you will need to deter
I've made some progress getting this test to run (see working patch below)
but I still get one failure:
not ok 28 # POSIX::errno(): 20, $!: not a directory
20 is the correct value for ENOTDIR, but how can POSIX::errno() and $! be
expected to be numerically equal when $! returns a string? Or i
On Wed, 7 Nov 2001, Craig A. Berry wrote:
> I've made some progress getting this test to run (see working patch below)
> but I still get one failure:
>
> not ok 28 # POSIX::errno(): 20, $!: not a directory
>
> 20 is the correct value for ENOTDIR, but how can POSIX::errno() and $! be
> expecte
This patch adds a basic explanation of what testing bits can be used
in what tests.
Taking it's own advice, it modernizes the patch example to use
t/test.pl and is().
--- pod/perlhack.pod2001/11/07 20:32:08 1.1
+++ pod/perlhack.pod2001/11/07 20:50:18
@@ -1531,47 +1531,42 @@
Unicode
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