I will be out of the office starting 08/01/2006 and will not return until
08/02/2006.
On August 1 2006 I can be reached at 416 457 7180. Regards.
---
This e-mail message (including attachments, if any) is intended for the u
I will be out of the office starting 08/01/2006 and will not return until
08/02/2006.
On August 1 2006 I can be reached at 416 457 7180. Regards.
---
This e-mail message (including attachments, if any) is intended for the u
Title: Regular expression question
From:
[EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of
Cai, Lucy (L.)Sent: Monday, July 31, 2006 17:21To:
Cai, Lucy (L.); perl-win32-users@listserv.ActiveState.com;
perl-unix-users@listserv.ActiveState.com;
[EMAIL PROTECTED];
[EMAIL PROTECTED]Sub
Title: Regular expression question
Try something like:
my ($dir , $filename) = $file=
~ /^(.*?)\\([^\\]*?)$/ ;
From:
[EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of<
/B>Cai, Lucy (L.)Sent: Monday, July 31, 2006 8:21 PMTo:
Cai, Lucy (L.); perl-win32-users@listserv.ActiveSt
Title: Regular expression question
I have a file such as:
My $file = "c:\temp\zips\ok.txt";
How can I split the $file to get the only path:
My $dir = "c:\temp\zips";
My $file = "ok.txt";
Thanks in advance!
Lucy
___
Perl-Unix-Users mail
Title: Regular expression question
I have a file such as:
My $file = "c:\temp\zips\ok.txt";
How can I split the $file to get the only path:
My $dir = "c:\temp\zips";
My $file = "ok.txt";
Thanks in advance!
Lucy
___
Perl-Unix-Users ma
