On Fri, 4 Jul 2003, M Ajmal wrote:
> Hi,
>
> I'm parsing a file and want to eliminate all lines
> that start with "Test" and end with "PASS!". I'm
> trying to do the following:
>
> /^Test.+PASS!$/
>
> but it says no patterns match!
>
> Some help please.
Show more code, please.
[EMAIL PROTEC
On Fri, 4 Jul 2003, Beckett Richard-qswi266 wrote:
> Isn't it because the ! hasn't been escaped with a \ that it doesn't work?
>
> That's what I thought, hence:
>
> /^Test.+PASS\!$/
>
> This seems to work nicely.
>
-
The ! is not a regex metacharacter so it doe
thanks for the help...
I ended up solving the problem.. The reg-ex that
worked was:
/^Test.\+PASS!$/
For some reason, the "+" sign had to be escaped; yet,
the "!" sign (which I thought for sure was something
special) isnt'... :-)
MA
PS: It's amazing how much watching the reg-ex matching
the pa
This works for me...
/^Test.*PASS\!$/
Use this little script to check out your pattern matches:
while (<>) {
chomp;
if (/^Test.*PASS\!$/) {
print "Matched: |$`<$&>'|\n";
} else {
print "No match.\n";
}
}
R.
> -Original Message
You may have a space at the begriming that is not obvious. Try cutting and
pasting a line that contains an exact copy of a line you want to match into
your code then slowly remove the specific characters replacing them with
regular expressions to find your error.
Respectfully,
Paul
> [Original
