Re: RES: Getting file name from a path

2007-04-13 Thread Andy_Bach
> Often I need to extract the file name from a path. $current_file = "c:/somedir/test.ps"; @split_path = split("/",$current_file); $current_file = @split_path[-1]; print $current_file; You want to use the '$' sigil here, not '@' (you're refering to just one element, not the whole array): $cur

RES: Getting file name from a path

2007-04-13 Thread Fabricio Soares Martins - Site CBN - SGR
try this: #!/perl -w $current_file = "c:/somedir/test.ps"; $current_file =~ /.*(\/|\\)(.*)/gi; print $2; :) fabrício s. martins -Mensagem original- De: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] nome de John Townsend Enviada em: sexta-feira, 13 de abril de 2007 17:53 Para: [EMAI