hi,
i came across this statement while reading Perlop. I don't understand how %s
is substituted w/ "s" or w/o "s" depending on the no. of dogs. %s is a hash.
how is it associated w/ the ?: operator?
it prints " i have 0 dogs." but if i change 1 to 0, it prints "i have 0
dog."
grateful for your
thanks for all the people who answered
i have a @list that contains elements i do not know. i'm using grep to
match
some words inside the @list.
for example:
$match = grep /\d/, @list;
my question is: is there a way to find the element No. eg:
$list[number] of
the latest match?
hi perl friends,
i have a @list that contains elements i do not know. i'm using grep to match
some words inside the @list.
for example:
$match = grep /\d/, @list;
my question is: is there a way to find the element No. eg: $list[number] of
the
latest match?
thanks!
---
You are currently
i tried tr/\\/B\//d;
to delete all the /B inside the $File variable wherein i slurped the
entire HTML(because i needed to read across multiple lines), but the
transliteration doesn't seem to work. can anyone help? i opened the HTML
file and some of them have words or characters immediately(w/o
pls. help me understand. what does the "!" mean below? does it mean "not"?
On 05/12/00, "[EMAIL PROTECTED]" wrote:
Doug, while your posts are always full of useful info, you made
a typo or two in this one. You wrote:
my @filelist = grep { !/^.+/ } readdir DIR;
Oops! Must have been
hi,
when you want to get rid of newlines and carriage returns, is it correct to
use:
tr/\n\r//g; ?
below you suggested tr/\x0a\x0d//d;
what does "x0a" and "x0d" mean?
where can i get a list of all these strange characters and their meaning?
a few days ago, Bill suggested : tr/015d//g; to get
how do I use the s/ / / to read/match and then later to write/substitute
words into the same existing file? i tried this below but it just wipes out
my entire file.
#!/usr/bin/perl
open(TEST, "test.txt") or die "Can't open PRICE: $!\n";
$file = TEST;
$file =~ s/jimmy/thomas/;
y any
character or characters along the way UNTIL (then stop) you find an E with 3
digits plus a - or w/o a - followed by 4 digits, then return the
match.
but i still get return of everything. Perl seems
to ignore my ?! negative look ahead. is this because of the * i have? how do i
solve this?
jimmy
hi all,
how do you escape a "." (dot)? i would like do a pattern match w/ a "."
within the pattern.
thanks in advance!
jim
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