[perl #61892] list-comprehension assignments with declaration

2009-01-11 Thread Patrick R. Michaud via RT
On Thu Jan 01 10:16:14 2009, dave.wh...@gmail.com wrote: > I've been trying to figure out how to do a "($hd, @tl) = @list" assignments. > > ./perl6 -e ' > my @list = 1,2,3; > my ($hd, @tl) = @list; > say ([$hd], [...@tl]).perl > ' > [[1], []] Now working as of 35397: $ cat x my @

[perl #61892] list-comprehension assignments with declaration

2009-01-01 Thread Dave Whipp
# New Ticket Created by "Dave Whipp" # Please include the string: [perl #61892] # in the subject line of all future correspondence about this issue. # http://rt.perl.org/rt3/Ticket/Display.html?id=61892 > (rakudo 34751) I've been trying to figure out how to do a "($hd, @tl) = @list" assignme