Hello Liz,
I was indeed talking about the unshaped situation.
BTW. I am growing more and more fond of raku,
Thanks,
Theo
Elizabeth Mattijsen schreef op 2021-02-05 16:06:
On 5 Feb 2021, at 15:49, Theo van den Heuvel
wrote:
I cannot seem to find an idiomatic way to get the dimensions of a
I think he meant doing something like this (with fuller handling for out of
bounds, exceptions throwing, slices, etc):
role Shaped[*@dimensions] {
has @!multipliers =
@dimensions.reverse.produce(&[*])[0..*-2].reverse.Slip, 1;
method AT-POS(*@indices where all @dimensions Z>
When will we have p6’s Numpy?
On Sat, Feb 6, 2021, at 2:04 AM, Brad Gilbert wrote:
> There is a reason that you can't just ask for the dimensions of an
> unspecified multidimensional array.
> It may be multiple dimensions.
>
> [[1,2,3],
> [4,5,6,7,8,9,10]].shape
>
> If it gave a
There is a reason that you can't just ask for the dimensions of an
unspecified multidimensional array.
It may be multiple dimensions.
[[1,2,3],
[4,5,6,7,8,9,10]].shape
If it gave a result it would be something like:
(2,3|7)
On Fri, Feb 5, 2021 at 8:50 AM Theo van den Heuvel
wrote:
Shaped Arrays and Native Shaped Arrays already use one contiguous blob
to store all their data; in Shaped Arrays that's an array of pointers to
the stored objects, in a Native Shaped Array it'll be like a big array
of 32bit integers or whatever you have.
Regards
- Timo
On 05/02/2021 16:48,
This got me interested in
https://docs.raku.org/language/list#index-entry-Shaped_arrays
and I find myself wanting to implement a role "Shaped" and applying it to
List, for an immutable shaped list, whose implementation packs its elements
for o(1) lookup... on my ever-lengthening to-do list
-y
> On 5 Feb 2021, at 15:49, Theo van den Heuvel wrote:
> I cannot seem to find an idiomatic way to get the dimensions of a
> multidimensional array,
> other than by looking at the size of the first row and column, with
> @m[0;*].elems and @m[*;0].elems.
> Am I missing something in the docs?
If
