Re: reverse of .lines?

2017-02-18 Thread Timo Paulssen
On 18/02/17 06:09, ToddAndMargo wrote: > On 02/17/2017 07:44 PM, yary wrote: >> Oh, then chain join on the end: >> >> my $StringReversedLines = >> $StringFullOfLineFeeds.lines.reverse.join("\n") >> >> or >> >> my $StringReversedLines = >> $StringFullOfLineFeeds.split("\n",:v).reverse.join >>

Re: reverse of .lines?

2017-02-17 Thread ToddAndMargo
On 02/17/2017 07:44 PM, yary wrote: Oh, then chain join on the end: my $StringReversedLines = $StringFullOfLineFeeds.lines.reverse.join("\n") or my $StringReversedLines = $StringFullOfLineFeeds.split("\n",:v).reverse.join **//___^ Hmmm. I wanted to recreate the array, not reverse the

Re: reverse of .lines?

2017-02-17 Thread ToddAndMargo
On 02/17/2017 07:44 PM, yary wrote: my $StringReversedLines = $StringFullOfLineFeeds.lines.reverse.join("\n") or my $StringReversedLines = $StringFullOfLineFeeds.split("\n",:v).reverse.join **//___^ Cool. I was wondering how to put the line feed back in! -- ~~~

Re: reverse of .lines?

2017-02-17 Thread ToddAndMargo
On 02/17/2017 07:26 PM, yary wrote: On Fri, Feb 17, 2017 at 9:52 PM, ToddAndMargo > wrote: @Lines = $StringFullOfLineFeeds.lines @Lines = $StringFullOfLineFeeds.lines.reverse -y Thank you! -- ~~

Re: reverse of .lines?

2017-02-17 Thread yary
Oh, then chain join on the end: my $StringReversedLines = $StringFullOfLineFeeds.lines.reverse.join("\n") or my $StringReversedLines = $StringFullOfLineFeeds.split("\n",:v).reverse.join

Re: reverse of .lines?

2017-02-17 Thread Brandon Allbery
On Fri, Feb 17, 2017 at 10:26 PM, yary wrote: > On Fri, Feb 17, 2017 at 9:52 PM, ToddAndMargo > wrote: > >> @Lines = $StringFullOfLineFeeds.lines > > > @Lines = $StringFullOfLineFeeds.lines.reverse They want what Haskell calls unlines, not a reversed

Re: reverse of .lines?

2017-02-17 Thread yary
On Fri, Feb 17, 2017 at 9:52 PM, ToddAndMargo wrote: > @Lines = $StringFullOfLineFeeds.lines @Lines = $StringFullOfLineFeeds.lines.reverse -y