Extended case: if the "of" clause comes after an "is default" clause,
then the explicit default is not subjected to the type constraint.
Other behaviour remains the same.
$ ./perl6 -e 'my $a is default("foo") of Int; say $a'
foo
$ ./perl6 -e 'my $a is default("foo") of Int; $a = $a; say $a'
Type c
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$ ./perl6 -e 'say Real.new'
[hangs]
^C
Like Numeric.new + 0 [perl #126112], there's a hang on
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cheers as we have $~Main and $~Rregex , $~Quote should also be whole word for
consist
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$ ./perl6 -e 'sub aa (Mu:wibble $a) { }; say "hi"'
hi
The :wibble, having no defined meaning,
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$ ./perl6 -e 'say 3.isa(Mu:U)'
True
That's not the right answer for what I want Mu:U to do. A
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Playing around trying to get a definedness constraint on a variable
(which I now understand is
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$ ./perl6 -e 'sub aa (Mu:D $a) { }; aa(Int)'
Parameter '$a' requires an instance of type Int, b
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S02 says this will produce a compiler error:
$ ./perl6 -e 'my Int $a of Str; say "hi"'
hi
The
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Reusing again the function I explained in [perl #126119], let's look
at 1950:
$ ./perl6 -e 'su
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Reusing the function I explained in [perl #126119], let's look at 1970:
$ ./perl6 -e 'sub leap
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[19:22:03] m: role R { has int $!a }; class A does R { method a()
{ $!a = 42
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The Instant class supposedly represents times on the TAI time scale,
with subtraction of Instan
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$ ./perl6 -e 'sub aa (Mu:U ::T) { say T; my T $a = T; say $a.WHAT; }; aa(Int);
aa(Nil)'
(Int)
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How nice to be able to use a constant declaration to give a local name
to a (possibly complex)
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Because a type object is an (undefined) instance of that type, it can
in general be stored in a
On 09/20/2015 09:55 AM, Tobias Leich (via RT) wrote:
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>
> t/spec/S02-names/pseud
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Failure.new is a perfectly valid value that can be stored in a scalar
variable:
$ ./perl6 -e '
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t/spec/S02-names/pseudo.t expects that you can do:
use Test; plan 1;
sub f3() {
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