# New Ticket Created by Will Coleda
# Please include the string: [perl #76842]
# in the subject line of all future correspondence about this issue.
# URL: http://rt.perl.org/rt3/Ticket/Display.html?id=76842
twitterbugged @ http://twitter.com/mfollett/status/19919694472 :
- Interesting
What is assigning a Range to an array supposed to do? Give you an
array of one item which is a Range? Convert to a series?
On Friday, July 30, 2010, Will Coleda perl6-bugs-follo...@perl.org wrote:
# New Ticket Created by Will Coleda
# Please include the string: [perl #76842]
# in the
What is assigning a Range to an array supposed to do? Give you an
array of one item which is a Range? Convert to a series?
On Friday, July 30, 2010, Will Coleda perl6-bugs-follo...@perl.org wrote:
# New Ticket Created by Will Coleda
# Please include the string: [perl #76842]
# in the
On Fri, Jul 30, 2010 at 01:22:02PM -0400, Mark J. Reed wrote:
What is assigning a Range to an array supposed to do? Give you an
array of one item which is a Range? Convert to a series?
A range in list context becomes a list of successive values in
the Range.
my @foo = 1..*;
causes
Right. So,
my $foo = 1..*;
$foo.max;
Should return Inf; likewise
my @foo = 1...*;
@foo.max;
Should behave like
(1...*).max
...that is, I expect both not to terminate. It's the conversion to
array that is the break in the original example, not the act of
assigning to a variable.
This .. vs
