On Wed, Sep 01, 2004 at 07:08:57PM +0200, Juerd wrote:
: Larry Wall skribis 2004-09-01 8:02 (-0700):
: > : $x.transform.();
: > That might not work either. This will, though:
: > ($x.transform)();
:
: This is surprising. Can you please explain why .() won't work? I have
: methods return su
Larry Wall skribis 2004-09-01 8:02 (-0700):
> : $x.transform.();
> That might not work either. This will, though:
> ($x.transform)();
This is surprising. Can you please explain why .() won't work? I have
methods return subs quite often, and like that I can just attach ->() to
it to make
On Wed, Sep 01, 2004 at 08:02:33AM -0700, Larry Wall wrote:
: That might not work either. This will, though:
:
: ($x.transform)();
So will
$x.transform()();
for that matter...
Larry
On Wed, Sep 01, 2004 at 10:41:37AM -0400, Aaron Sherman wrote:
: How do you declare attribute functions? Specifically, I was thinking
: about map and what kind of object it would return, and I stumbled on a
: confusing point:
:
: class mapper does iterator {
: has &.transform;
How do you declare attribute functions? Specifically, I was thinking
about map and what kind of object it would return, and I stumbled on a
confusing point:
class mapper does iterator {
has &.transform;
...
}
Ok, that's fine, but what kind of access
