Nathan, thanks for zeroing in on this paragraph from RFC 23. It raises a
question in my mind about the meaning of the RFC, and whether the paragraph is
even necessary, which could answer your question about implementation.
If a curried subroutine is truly generated because of seeing an
The subroutines generated by a placeholder are not exactly like
the equivalent subroutines shown above. If they are called with
fewer than the required number of arguments, they return another
higher order function, which now has the specified arguments
bound as well.
Damian Conway wrote:
You're error is in assuming I have time *now*.
With 30+ RFCs still to write, I've been seriously contemplating
just abandoning the Perl 6 effort, because added to the demands
of my full-time job, my O'Reilly and other tutorial commitments,
my modules, and my poor
On Sat, Aug 19, 2000 at 06:35:55AM +1000, Damian Conway wrote:
You're error is in assuming I have time *now*.
With 30+ RFCs still to write, I've been seriously contemplating
just abandoning the Perl 6 effort, because added to the demands
of my full-time job, my O'Reilly and other tutorial
Glenn Linderman wrote:
Nathan, thanks for zeroing in on this paragraph from RFC 23. It raises a
question in my mind about the meaning of the RFC, and whether the paragraph is
even necessary, which could answer your question about implementation.
If a curried subroutine is truly generated
[Apologies for following-up my own post]
I wrote:
You're error is in assuming I have time *now*.
With 30+ RFCs still to write, I've been seriously contemplating
just abandoning the Perl 6 effort, because added to the demands
of my full-time job, my O'Reilly and other
Damian Conway wrote:
It was simply attempting to explain why I choose to ignore what are (to
me, at least) trivial implementation issues, well documented in the
compiler literature. I choose to ignore them because I *have* to ignore
them or my brain is going to melt.
So perhaps you should
Damian Conway writes:
$add = ^a + ^b;
# a thousand lines later...
$incr = $add-(1);
# a thousand lines later...
$x = $incr-($x);
I picture $add-(1) cloning add's optree, filling in the 1 where
appropriate, then returning a reference to the new (cloned) optree.
If there are any RFC's which you have in mind and could send me your
notes on, I'd be *more* than happy to help out.
This is actually an excellent idea, because then Damian can
concentrate on coming up with the key ideas. However, rather than
having to shuffle notes
