Zhuang Li wrote:
Yes. I think it's both useful and fun. I was thinking something similar
to
@[EMAIL PROTECTED] = map{1} @a;
But getting $hash-{E1}-{E2}-...-{En} = 1; instead of $hash{E1} =
1; ... $hash{En} =1;.
What I'd really like to do is:
Given @a = ('E1', 'E2', ..., 'En');
@b =
Zhuang Li writes:
Yes. I think it's both useful and fun. I was thinking something similar
to
@[EMAIL PROTECTED] = map{1} @a;
But getting $hash-{E1}-{E2}-...-{En} = 1; instead of $hash{E1} =
1; ... $hash{En} =1;.
Yeah, like this:
%hash{dims @a} = (1) xx Inf;
What I'd really like to
-Original Message-
From: Luke Palmer [mailto:[EMAIL PROTECTED]
Sent: Tuesday, March 29, 2005 5:43 AM
To: Zhuang Li
Cc: Jeff Yoak; fwp@perl.org; perl6-language@perl.org
Subject: Re: Unknown level of hash
Zhuang Li writes:
Yes. I think it's both useful and fun. I was thinking
ZL == Zhuang Li [EMAIL PROTECTED] writes:
ZL Hi, given an array: @a = ('E1', 'E2', ..., 'En');
ZL Is there an easy way, hopefully one liner, to do the following without a
ZL loop? If not, will Perl support this in Perl 6?
ZL $hash-{E1}-{E2}-...-{En} = 1;
i think perl6 plans to have a
To: Zhuang Li
Cc: fwp@perl.org
Subject: Re: Unknown level of hash
On Mon, 2005-03-28 at 15:06, Zhuang Li wrote:
Hi, given an array: @a = ('E1', 'E2', ..., 'En');
Is there an easy way, hopefully one liner, to do the following
without a
loop? If not, will Perl support this in Perl 6
