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· The sentence essentially means For a radix of 12, use the
Mark J. Reed wrote:
I read the statement use A or B for base 12, not T or E as meaning
for the values ten and eleven in base 12, use :12A and :12B, not
:12T and :12E.
Does it say anywhere that you can use non-decimal notation for the
radix specifier itself? 'Cause that strikes me as
This is just a reminder that I have files posted at
http://www.dlugosz.com/Perl6/offerings/ waiting for someone in
authority to inspect and merge.
TSa Thomas.Sandlass-at-vts-systems.de |Perl 6| wrote:
Taking only the lhs into account doesn't work in Patrick's
code because he has untyped variables. The Dog is only on
the rhs. This is why I think we need a binary dispatch. I
don't see much use for the type of the LHS, though. C++
dispatches
Patrick R. Michaud wrote:
In [1], Larry writes:
[...] we left = in the language
to provide (to the extent possible) the same semantics that it
does in Perl 5. And when it comes to non-value types, there really
are still references, even if we try not to talk about them much.
So I think
On Mon, Sep 15, 2008 at 06:08:37PM -0500, John M. Dlugosz wrote:
This is just a reminder that I have files posted at
http://www.dlugosz.com/Perl6/offerings/ waiting for someone in
authority to inspect and merge.
Would it be worthwhile to provide them as diffs? That way we
could easily see
Darren Duncan darren-at-darrenduncan.net |Perl 6| wrote:
So, how does one get an object to pretend to be a value type for
purposes of assignment?
Currently if I do the following
class Dog { ... }
my $a = Dog.new;
my $b = $a;
then $a and $b both refer to the same Dog object. How
On Mon, Sep 15, 2008 at 10:09:41PM -0500, John M. Dlugosz wrote:
Darren Duncan darren-at-darrenduncan.net |Perl 6| wrote:
So, how does one get an object to pretend to be a value type for
purposes of assignment?
I have been under the impression that value types are supposed to
define
