Jon Lang datawea...@gmail.com writes:
So $a -= $b is equivalent to $b = $a, not -($a = $b). OK.
I'd suggest choosing a better character for the meta-operator (one
that conveys the meaning of reversal of order rather than opposite
value); but I don't think that there is one.
A
I took the quotation marks to indicate an intentional
misspelling/coinage: perl + prelude = perlude.
On 1/29/09, Moritz Lenz mor...@faui2k3.org wrote:
pugs-comm...@feather.perl6.nl wrote:
+PERL# Lexical symbols in the standard perlude
Did you mean prelude instead?
Moritz
On Thu, Jan 29, 2009 at 09:00:06AM +0100, Eirik Berg Hanssen wrote:
: Jon Lang datawea...@gmail.com writes:
:
: So $a -= $b is equivalent to $b = $a, not -($a = $b). OK.
: I'd suggest choosing a better character for the meta-operator (one
: that conveys the meaning of reversal of order
Author: lwall
Date: 2009-01-29 21:32:51 +0100 (Thu, 29 Jan 2009)
New Revision: 25113
Modified:
docs/Perl6/Spec/S03-operators.pod
src/perl6/STD.pm
Log:
[STD, S03] slaughter of the LTM metatokens
STD now runs considerably faster
Freed from LTM, metaoperators may now be nested arbitrarily deep
