Larry Wall writes:
On Wed, Jan 21, 2004 at 08:51:33PM -0500, Joe Gottman wrote:
: Great, so
: $x = foo(), bar();
: means the same thing as
: $x = ( foo(), bar() );
No, we haven't changed the relative precedence of assignment and
comma. I've been tempted to, but I always come
On Tue, Jan 20, 2004 at 08:12:28PM -0800, Jonathan Lang wrote:
: Joe Gottman wrote:
: About a month ago, a thread here suggested that we change the meaning
: of the comma operator. Currently, in scalar context the expression
: foo(), bar()
: means evaluate foo(), discard the result
- Original Message -
From: Larry Wall [EMAIL PROTECTED]
To: Perl6 [EMAIL PROTECTED]
Sent: Wednesday, January 21, 2004 2:51 PM
Subject: [perl] Re: Comma Operator
On Tue, Jan 20, 2004 at 08:12:28PM -0800, Jonathan Lang wrote:
: Joe Gottman wrote:
: About a month ago, a thread here
Joe Gottman wrote:
About a month ago, a thread here suggested that we change the meaning
of the comma operator. Currently, in scalar context the expression
foo(), bar()
means evaluate foo(), discard the result, then return the value of
bar().
It was suggested that this be changed
