On Thu, 25 Nov 2004, Larry Wall wrote:
On Thu, Nov 25, 2004 at 11:59:21AM -0600, Rod Adams wrote:
: Seeing the « in the context of a here-doc made me think can you do a
: » here-doc?
Nope, you can only hyper operators, not terms.
Incidentally, just like mathematically (albeit slightly loosely) an
Incidentally, just like mathematically (albeit slightly loosely) an
element of a set can be thought of as a function from any singleton,
would it be possible for Perl 6 to provide a fast (under the
syntactical point of view) way to promote a term to a function
returning it?
What's wrong with
On Tue, 30 Nov 2004, David Christensen wrote:
Incidentally, just like mathematically (albeit slightly loosely) an element
of a set can be thought of as a function from any singleton, would it be
possible for Perl 6 to provide a fast (under the syntactical point of view)
way to promote a term to
On Tue, 30 Nov 2004, David Christensen wrote:
Incidentally, just like mathematically (albeit slightly loosely) an
element of a set can be thought of as a function from any singleton,
would it be possible for Perl 6 to provide a fast (under the syntactical
On Tue, 30 Nov 2004, Abhijit Mahabal wrote:
or the perl6
$xsub = { $x };
Sorry, I was missing the obvious...
Michele
--
[...] is like requiring to play tennis with a square ball.
Which admittedly makes the game more interesting.
- Giuseppe Oblomov Bilotta in comp.text.tex (edited)
Juerd wrote:
Thomas Seiler skribis 2004-11-25 14:52 (+0100):
Is $heredoc = «END; the same as $heredoc = END; ?
I certainly hope not.
Quoting the delimiter is needed, by the way.
How is 'END' disambiguated from 'qw' list, anyway?
Seeing the « in the context of a here-doc made me think
On Thu, Nov 25, 2004 at 11:59:21AM -0600, Rod Adams wrote:
: Seeing the « in the context of a here-doc made me think can you do a
: » here-doc?
Nope, you can only hyper operators, not terms.
: So, something like :
:
: @text = »END;
: text1
: END
:
: text2
: END
:
: text3
: END
:
: text4
:
