Just wondering - would 'reverse =$foo' call '$foo.previous()' ?
- Flavio
2005/7/29, Aankhen <[EMAIL PROTECTED]>:
> On 7/29/05, Flavio S. Glock <[EMAIL PROTECTED]> wrote:
> > Is "for =" only for filehandles? I tried:
>
> No, it's for anything that supports iteration... `=$foo` ==
> `$foo.next()`,
On 7/29/05, Flavio S. Glock <[EMAIL PROTECTED]> wrote:
> Is "for =" only for filehandles? I tried:
No, it's for anything that supports iteration... `=$foo` ==
`$foo.next()`, if I recall correctly. It's probably not yet
implemented.
Aankhen
On Thu, Jul 28, 2005 at 19:58:16 -0300, Flavio S. Glock wrote:
> 2005/7/28, Yuval Kogman <[EMAIL PROTECTED]>:
> >
> > I think unary = is what you want:
> >
> > my @a = $span.lazy;
> >
> > for [EMAIL PROTECTED] -> $item {
> > ...
> > }
> >
> > Ofcourse, my
2005/7/28, Yuval Kogman <[EMAIL PROTECTED]>:
>
> I think unary = is what you want:
>
> my @a = $span.lazy;
>
> for [EMAIL PROTECTED] -> $item {
> ...
> }
>
> Ofcourse, my @a = $span.lazy will have to be fixed, but what you
> tried should be working.
Is "f
On Wed, Jul 27, 2005 at 20:17:41 -0300, Flavio S. Glock wrote:
> I have an object representing the sequence "1..Inf".
> I tried creating a Coroutine, and then assigning the Coroutine to an
> Array, but it only yielded "1":
>
> my @a = $span.lazy; # "1"
>
> The coroutine worked fine in a "whil
How can I create a lazy list from an object?
I have an object representing the sequence "1..Inf".
I tried creating a Coroutine, and then assigning the Coroutine to an
Array, but it only yielded "1":
my @a = $span.lazy; # "1"
The coroutine worked fine in a "while" loop, but it didn't work in
