I consider recursive regexps very useful:
$a = qr{ (? [^()]+ ) | \( (??{ $a }) \) };
Yes, they're "useful", but darned tricky sometimes, and in
ways other than simple regex-related stuff. For example,
consider what happens if you do
my $regex = qr{ (? [^()]+ ) | \( (??{ $regex }) \)
In [EMAIL PROTECTED], Tom Christiansen writes:
:I consider recursive regexps very useful:
:
: $a = qr{ (? [^()]+ ) | \( (??{ $a }) \) };
:
:Yes, they're "useful", but darned tricky sometimes, and in
:ways other than simple regex-related stuff. For example,
:consider what happens if you do
:
On Thu, Sep 28, 2000 at 08:57:39PM -, Perl6 RFC Librarian wrote:
${P1} means what $1 currently means (first match in last regex)
I'm sorry that I don't have anything more constructive to say than
"ick", but ... Ick.
Well, maybe I do. Forget $P1. If the user wanted $1 from the
previous
On Wed, 27 Sep 2000 10:34:48 -0500, Jonathan Scott Duff wrote:
If $1 could be made to work properly on the LHS of s///, I'd vote for
that being The Way.
I disagree, because \1 is different from a variable $foo in at least two
ways:
* $foo is compiled into /$foo/ before anything is matched. \1
:=item *
:/(foo)_$1_bar/
:
:=item *
:/(foo)_C\1_bar/
Please don't do this: write C/(foo)_\1_bar/ or /(foo)_\1_bar/, but
don't insert C in the middle: that makes it much more difficult to
read.
:mean different things: the second will match 'foo_foo_bar', while the
:first will match
In [EMAIL PROTECTED], Bart Lateur writes:
:I'll try to find that "thread" back.
This was my message:
http://www.mail-archive.com/perl6-language-regex%40perl.org/msg00354.html
:I don't think changing /s is the right solution. I think this will
:incline people to try and fix their problems by
Is $$ the only alternative, or did I miss more? I don't think I've even
seen this $$ mentioned before?
$$ is not a suitable alternative. It already means the current process
ID. It really cannot be messed with. And ${$} is identical to $$ by
definition.
I still like the idea of $$, as I
=item *
C\1 goes away as a special form
=item *
$1 means what C\1 currently means (first match in this regex)
=item *
${1} is the same as $1 (first match in this regex)
=item *
${P1} means what $1 currently means (first match in last regex)
Here's the big problem with this, and I
