Not long ago, Mark J. Reed proclaimed...
> What's the consensus on how to do an idiomatic countdown loop? I used
> for [1..$n].reverse...
This: will work eventually:
for $n..1:by(-1) { ... }
This currently works in rakudo:
for (1..$n).reverse { ... }
On Thu, Dec 25, 2008 at 1:55 AM, Stephen Weeks wrote:
> Not long ago, Mark J. Reed proclaimed...
>> What's the consensus on how to do an idiomatic countdown loop? I used
>> for [1..$n].reverse...
>
> This: will work eventually:
>for $n..1:by(-1) { ... }
Cool.
> This currently works in rakud
Not long ago, Mark J. Reed proclaimed...
> On Thu, Dec 25, 2008 at 1:55 AM, Stephen Weeks wrote:
> > This currently works in rakudo:
> >for (1..$n).reverse { ... }
>
> No, it doesn't (r34384)
>
> for (1..10).reverse { say $^i }
> 01 9 8 7 6 5 4 3 2 1
>
> The list is flattened into a string
Both pugs and rakudo agree on this one:
21:44 <@moritz_> perl6: my (@a, @b); @a.push(@b.pop); say @a.elems
21:44 < p6eval> ..pugs, rakudo 34399: OUTPUT«1»
pop'ping from an empty array returns an undef, which is then pushed onto @a.
Wouldn't it be nice of @empty_list.pop (or .unshift) would retu
