Author: lwall
Date: 2010-03-26 08:38:16 +0100 (Fri, 26 Mar 2010)
New Revision: 30205
Modified:
docs/Perl6/Spec/S02-bits.pod
docs/Perl6/Spec/S03-operators.pod
docs/Perl6/Spec/S05-regex.pod
docs/Perl6/Spec/S06-routines.pod
docs/Perl6/Spec/S12-objects.pod
Log:
[specs] Make it clear
Carl (), Darren ():
I didn't get it to trust me, though:
masak pugs: class A { has $!foo }; class B { trusts A; method bar(A
$a) { say $a!foo } }; B.new.bar(A.new(:bar(42)))
p6eval pugs: OUTPUT«»
Either it bitrotted or I'm using it wrong.
You're using it wrong. You need to put 'trusts
On Fri, Mar 26, 2010 at 7:16 AM, Carl Mäsak cma...@gmail.com wrote:
You're using it wrong. You need to put 'trusts B;' in A in order for B to
see A's privates. I hope it is obvious why this is the case. -- Darren
Duncan
Aye, my mistake. Apparently the syntax I used to try to get at the
On Fri, 2010-03-26 at 08:38 +0100, pugs-comm...@feather.perl6.nl wrote:
.doit: { $^a = $^b } # okay
.doit(): { $^a = $^b }# okay
.doit(1,2,3): { $^a = $^b } # okay
+.doit(1,2,3): { $^a = $^b } # okay
+.doit:{ $^a = $^b }
Author: lwall
Date: 2010-03-27 01:59:04 +0100 (Sat, 27 Mar 2010)
New Revision: 30211
Modified:
docs/Perl6/Spec/S12-objects.pod
Log:
[S12] pasto noticed by goeff++
Modified: docs/Perl6/Spec/S12-objects.pod
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