Technology, in common with many other activities, tends toward avoidance of
risks by investors. Uncertainty is ruled out if possible. Capital investment
follows this rule, since people generally prefer the predictable. Few recognize
how destructive this can be, how it imposes severe limits on
Hello,
Is it possible to create a new range operator ':' such that:
a:b is the same as a..b (this is the easy part)
a:b:c is a range from 'a' to 'b' by steps of 'c'. For example, 2:15:3
== 2,5,8,11,14
:b is the same as 0..b
a: is the same as a..Inf
::c is the same as 0:Inf:c
: is the same
On 03/21/2012 09:07 PM, Daniel Carrera wrote:
Hello,
Is it possible to create a new range operator ':' such that:
a:b is the same as a..b (this is the easy part)
a:b:c is a range from 'a' to 'b' by steps of 'c'. For example, 2:15:3
== 2,5,8,11,14
That can be done by giving the new
Hi Moritz
a:b is the same as a..b (this is the easy part)
a:b:c is a range from 'a' to 'b' by steps of 'c'. For example, 2:15:3
== 2,5,8,11,14
That can be done by giving the new infix:: operator list associativity
(niecza already supports this)
Can you explain or give me a link that
Is it possible to create a new range operator ':' such that:
Do you need to?
a:b:c is a range from 'a' to 'b' by steps of 'c'.
Perl 6 already has: $a,*+$c...* =$b
E.g. 2, 5 ...^ *=15 2,5,8,11,14
:b is the same as 0..b
Perl 6 already has ^$b
e,g, ^100 0..99
a: is the same
Daniel (), Damian ():
: is the same as 0..Inf
Perl 6 already has: ^Inf 0,1,2,3,4,5,
Hah, Damian made an off-by-one error! Oh wait...
// Carl
Damian (), Daniel ():
Perl 6 already has: 0,$c...*
e.g. 0,3...* 0, 3, 6, 9, 12
Interesting... but it doesn't seem to work in Rakudo Star (2012.02):
@(2,5..10)
2 5 6 7 8 9 10
:-(
Keep in mind that infix:.. will listify to the kind of
one-step-at-a-time range that was produced
Interesting... but it doesn't seem to work in Rakudo Star (2012.02):
@(2,5..10)
You need three dots, not two.
Damian
On 21 March 2012 22:50, Carl Mäsak cma...@gmail.com wrote:
It would also produce an infinite list, because by the rules you need
the RHS of infix:... to match exactly, and 10 is not in the infinite
list 2, 5, 8, 11, 14... Which is why you'd need to write something
like * = 10.
Ok, so
Ok, so infix:... isn't what I wish for either... Can you help me
understand Damian's example?
Breaking down that example:
$a, # Start at $a
*+$c # Generate next number via: sub($prev_num} { $prev_num + $c }
... # Repeat until...
* =$b # ...this sub matches:
On 22 March 2012 00:08, Brandon Allbery allber...@gmail.com wrote:
* + $c --- the next value is the current value plus $c. (* means
Whatever, and generally refers to the current value of something. In this
case, we're specifying how to make a new value given a current value. You
can think
On Wed, Mar 21, 2012 at 7:52 PM, Daniel Carrera dcarr...@gmail.com wrote:
* = $b --- this determines where the sequence ends: when the current value
is greater or equal to $b.
So... after the ... you have an anonymous function that has to
return 'True' for the sequence to end? Seems
On 22 March 2012 01:13, Solomon Foster colo...@gmail.com wrote:
It actually smartmatches whatever is on the right hand side against
the sequence, and stops when the smartmatch returns True. It just
happens that you smartmatch an anonymous function, it executes the
function and returns its
My understanding is if you want to count by threes, starting at 2 and ending at
14, you should be able to write:
2, 5 ... 14
That is, the list-building operator looks at the previous two or three terms
preceding it to determine where to start and what step function to use, and
then looks
What I want to know is whether there's a way to define a step function that's
based in part or in whole on the current term's index. For example, how would
I use infix:... to generate the perfect squares between 0 and 100? Namely,
'0,1,4,9,16,25,36,49,64,81,100'. For example, is Perl 6 set
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