Brad Bowman wrote:
my $a = rand(); # runtime variable
my $result = one(any( sub { $a+1}, sub { $a-1} ),sub { $a+3 }).();
say $result.perl;
If $a was 0.5 I'd guess
$result = one(any(1.5, 0.5), 3.5)
is this the case?
IIRC the .perl method produces a string from which an equal value
can be
Hi,
Assuming this is allowed, what will the .() calls below return?
Does the result depend on the calling context?
use junctions; # still required?
my @subs = ( sub { return 1 } ,
sub { return 2 } );
# call the closures in the junction
any(@subs).();
all(@subs).();
Brad Bowman wrote:
Assuming this is allowed, what will the .() calls below return?
Does the result depend on the calling context?
...
one(any(@subs),sub { ... }).();
Starting to argument from the statement that junctions are values
the above plays in the league of 3.() which might not have
