In data 28 mai 2009 alle ore 00:13:19, Mark J. Reed markjr...@gmail.com
ha scritto:
You can write a sub to return the next step:
sub bondigi { state $n=1; return (Bon Digi Bon Digi, Bon xx $n,
Digi xx $n++); }
Nahh. That's too easy...
It's not fun :-)
but I think an idiomatic Perl 6
Mark ():
but I think an idiomatic Perl 6 solution would have a proper lazy
Iterator. How do we write one of those?
Like this, I think:
$ perl6 -e '.say for gather { my $n = 1; loop { take bon digi bon
digi; take bon for ^$n; take digi for ^$n; ++$n } }'
That currently parses in Rakudo, but
In data 27 mai 2009 alle ore 23:46:40, John M. Dlugosz
2nb81l...@sneakemail.com ha scritto:
Anything in the existing implementation that's hostile to Perl 6? Just
port it over by lightly editing the text or using a p5 module importer.
Yes, right, but that wouldn't use Perl 6 features.
To
Hi cool people,
the Amazing Perl 6 thread was amazing.
It reminded me how Perl 6 looks interesting and fun.
So...
how can I write properly, for some meaning of properly,
the Perl 6 equivalent of this:
http://search.cpan.org/dist/Games-BonDigi/
?
(
if it's not clear, you can run the
Cosimo ():
the Amazing Perl 6 thread was amazing.
It reminded me how Perl 6 looks interesting and fun.
So...
how can I write properly, for some meaning of properly,
the Perl 6 equivalent of this:
http://search.cpan.org/dist/Games-BonDigi/
?
Not sure if I grokked the whole set of rules,
Cosimo Streppone cosimo-at-streppone.it |Perl 6| wrote:
Hi cool people,
the Amazing Perl 6 thread was amazing.
It reminded me how Perl 6 looks interesting and fun.
So...
how can I write properly, for some meaning of properly,
the Perl 6 equivalent of this:
Em Qua, 2009-05-27 às 23:46 +0200, Carl Mäsak escreveu:
Not sure if I grokked the whole set of rules, but here's a one-liner
that does it:
$ perl6 -e 'say (bon digi bon digi, bon xx ++$*n, digi xx
$*n).join(, ) while *'
It does, but it would be prettier if it was lazy...
for 2..* - $n {
(bon
You can write a sub to return the next step:
sub bondigi { state $n=1; return (Bon Digi Bon Digi, Bon xx $n,
Digi xx $n++); }
but I think an idiomatic Perl 6 solution would have a proper lazy
Iterator. How do we write one of those?
