Should !~~ /regex/ set $/?

[Moritz Lenz]

The subject says it all: should !~~ with a regex on the RHS set $/?

Cheers,
Moritz

-- 
Moritz Lenz
http://moritz.faui2k3.org/ |  http://perl-6.de/

Re: Should !~~ /regex/ set $/?

[Larry Wall]

On Sat, Sep 06, 2008 at 11:44:05AM +0200, Moritz Lenz wrote:
: The subject says it all: should !~~ with a regex on the RHS set $/?

For now I would assume that the meta operator rewrites

$a !~~ $b

to

(not $a ~~ $b)

so .ACCEPTS has no clue that it is dealing with a negated operator.
In other words, it sets $/ just like the normal ~~ operator, but
the boolean sense comes out backwards:

if $a !~~ /foo/ {
# $/ is false
}
else {
# $/ is true
}

Larry

Re: Should !~~ /regex/ set $/?

[Nicholas Clark]

On Sat, Sep 06, 2008 at 09:41:07AM -0700, Larry Wall wrote:
 On Sat, Sep 06, 2008 at 11:44:05AM +0200, Moritz Lenz wrote:
 : The subject says it all: should !~~ with a regex on the RHS set $/?
 
 For now I would assume that the meta operator rewrites
 
 $a !~~ $b
 
 to
 
 (not $a ~~ $b)

Perl 5 still does exactly this - there is no !~ opcode - the compiler just
generates the optree for ! of =~, and it is indistinguishable from it:

$ perl -MO=Deparse -e 'print if $^X !~ /perl/'
print $_ if not $^X =~ /perl/;
-e syntax OK
$ perl -MO=Deparse -e 'print if not $^X =~ /perl/'
print $_ if not $^X =~ /perl/;
-e syntax OK

Nicholas Clark