On Sun, Dec 04, 2005 at 01:10:44PM -0500, Mike Li wrote:
> what is a good translation of the following C into perl6?
[snip]
>
> in perl5, i would've written something like:
>
>
> my $x = 0; my @y = 1..9; @y[$x++]++; print "$x\n"; print "@y\n"
>
>
> but in perl6, the '@' sigil always means list
On Sun, 2005-12-04 at 13:10 -0500, Mike Li wrote:
> what is a good translation of the following C into perl6?
>
[...]
>int x = 0; int y[] = {1, 2, 3, 4, 5, 6, 7, 8, 9}; y[x++]++; /* line
> that matters */
[...]
>
>
> in perl5, i would've written something like:
>
> my $x = 0; my @y = 1..9
Mike Li skribis 2005-12-04 13:10 (-0500):
> in perl5, i would've written something like:
> my $x = 0; my @y = 1..9; @y[$x++]++; print "$x\n"; print "@y\n"
> but in perl6, the '@' sigil always means list context, so should i
> write the following?
> my $x = 0; my @y = 1..9; [EMAIL PROTECTED]
what is a good translation of the following C into perl6?
#include
void print(int y[])
{
int ii;
for (ii = 0; 9 > ii; ++ii)
{
printf("%d ", y[ii]);
}
printf("\n");
}
int main()
{
int x = 0; int y[] = {1, 2, 3, 4, 5, 6, 7, 8, 9}; y[x++]++; /* line
that matters */
p
