Date truncated-to method argument?

http://doc.perl6.org/type/Date says my $c = Date.new('2012-12-24'); say $c.truncated-to(:year); # 2012-01-01 but this doesn't work and what's implemented appears to be year rather than :year $ perl6 my $c = Date.new('2012-12-24'); 2012-12-24 say $c.truncated-to(year) 2012-01-01 Which is

Re: Date truncated-to method argument?

Hi, On 11/10/2014 01:39 PM, Steve Mynott wrote: http://doc.perl6.org/type/Date says my $c = Date.new('2012-12-24'); say $c.truncated-to(:year); # 2012-01-01 but this doesn't work and what's implemented appears to be year rather than :year $ perl6 my $c = Date.new('2012-12-24');