Hi Richard,
I wouldn't call s/// a routine. It's actually (implemented as) a kind of
quote, like Q, q, qq, qw, and also rx, and tr. I consider that an
important distinction, because the syntax with which you call s/// is
very different from how you call a sub. You can't just `say '(' ~ ')'
1234`,
Short answer: Yes.
Longer: Perl 6 allows you to over-ride the names of routines. 's' is a
routine. You over-rode it.
Perl 6 is different from most other languages because it uses multiple
dispatch. Effectively this means it is not just the name of the
subroutine (s) that matters, but also it
The following code:
use v6;
my $str = 'abc';
sub s {1};
say s;
$str ~~ s:g/ b /x/;
dd $str;
say $/;
outputs:
1
Str $str = "axc"
(｢b｣)
as expected.
But, just remove the :g global flag and:
===SORRY!=== Error while compiling /home/hogaboom/hogaboom/Perl6/p6ex/./t.p6
Undeclared routine:
