Re: What are Perl 6's killer advantages over Perl 5?

2015-08-26 Thread Brandon Allbery
On Wed, Aug 26, 2015 at 1:58 PM, Elizabeth Mattijsen l...@dijkmat.nl wrote: It used to be, but that was not according to spec. FROGGS++ implemented the lax mode, which is enabled by default in one-liners. Perhaps TimToady wants to invoke rule #2 on this. Personally, I use an alias that has

Re: What are Perl 6's killer advantages over Perl 5?

2015-08-26 Thread Elizabeth Mattijsen
On 26 Aug 2015, at 12:18, H.Merijn Brand h.m.br...@xs4all.nl wrote: On Wed, 26 Aug 2015 10:26:23 +0200, Moritz Lenz mor...@faui2k3.org wrote: I could continue with other Perl 5 deficiencies (no strict by default, Using strict *STILL* is not enabled by default for perl6 one-liners

Re: What are Perl 6's killer advantages over Perl 5?

2015-08-26 Thread Moritz Lenz
Hi, On 11.08.2015 14:12, Tom Browder wrote: I have seen several lists of new Perl 6 features (versus Perl 5) but they all seem to be lists that intermix features with varying degrees of value to ordinary Perl 5 users. If one wants to sell long-time Perl 5 users (already using the latest Perl

Re: What are Perl 6's killer advantages over Perl 5?

2015-08-26 Thread Tom Browder
On Wed, Aug 26, 2015 at 3:26 AM, Moritz Lenz mor...@faui2k3.org wrote: Hi, On 11.08.2015 14:12, Tom Browder wrote: I have seen several lists of new Perl 6 features (versus Perl 5) but they all seem to be lists that intermix features with varying degrees of value to ordinary Perl 5 users.

Formatting in Pod declarator blocks

2015-08-26 Thread Philip Hazelden
Synopsis 26 http://design.perl6.org/S26.html#Declarator_blocks says of declarator blocks: A declarator can have multiple leading and/or trailing Pod comments, in which case they are concatenated with an intermediate newline when their object's .WHY return value is stringified But the current

Re: What are Perl 6's killer advantages over Perl 5?

2015-08-26 Thread Marc Chantreux
On Wed, Aug 26, 2015 at 12:18:46PM +0200, H.Merijn Brand wrote: $ perl6 -e'my Int $this = 1; $thıs++; say $this;' 1 $ perl6 -Mstrict -e'my Int $this = 1; $thıs++; say $this;' ===SORRY!=== Error while compiling -e Variable '$thıs' is not declared. Did you mean '$this'? at -e:1 -- my Int