Hi All,
I wanted to do a mass rename of "Apple.*" to "Mac.*" with
bash and I could not figure out the error.
I eventually did find it and I have to blame Perl for it!
Chuckle.
for F in Apple*; do $G=$(echo $F | sed -e 's/^Apple/Mac/'); mv $F $G;
echo "$F --> $G"; done
Did you catch the erro
Yes; but then I think that something like infix: probably just ends up
as a macro somehow. I just didn't know the state of macros in Perl 6 well
enough to be able to head down that route. :)
Pm
On Fri, Aug 03, 2018 at 10:32:41PM +0200, Elizabeth Mattijsen wrote:
> Sometimes I wish we could us
On 08/03/2018 11:36 AM, Parrot Raiser wrote:
If I've interpreted this
https://docs.perl6.org/language/regexes#Enumerated_character_classes_and_ranges
correctly,
^ is "start of string"
+alnum means "in the alphanumeric set"
-alpha means "not in the purely alphabetic set"
i.e. <+alnum -alpha> me
On 08/03/2018 11:52 AM, Patrick R. Michaud wrote:
The + essentially indicates that this is a character-class match. It's to distinguish things from
<.alpha>, , , <-alpha>, and (among others).
Thank you!
On 08/03/2018 11:48 AM, Timo Paulssen wrote:
The + is required, perhaps because the first character after the opening
< is supposed to determine exactly what thing it is? Not sure about
that. The + and - is a bit like "start at nothing, add all alnums, then
subtract all alphas". The + after the <
Hi all,
My attempt at a solution below does not work. In larger examples the
decr gets called before the actions within Sum are processed. Maybe my
hunch that this would cause time order problems was correct. I need to
do some more researching. I'll post my findings.
best wishes,
Theo van
Sometimes I wish we could use Thunk as a type:
sub infix:(Thunk:D $block, $otherwise) { }
which would then allow you to do:
my $sixdivzero = divide(6,0) rescue -1; # note absence of curlies
One can wish, can’t one?
Liz
> On 3 Aug 2018, at 22:18, Patrick R. Michaud wrote:
>
> Maybe somet
Maybe something like...?
$ cat t.p6
sub infix:(Callable $block, $otherwise) {
CATCH { return $otherwise; }
$block();
}
sub divide($a, $b) { die "Zero denominator" if $b == 0; $a / $b }
my $sixdivzero = { divide(6,0) } rescue -1;
say "6/0 = ", $sixdivzero;
my $sixdivtwo = { divide(6,2) }
Hi Sean. I hope my second answer in stackoverflow gets closer to what you
want.
I am still trying to think of a more idiomatic way of handling to situation.
On Fri, 3 Aug 2018, 19:29 Sean McAfee, wrote:
> I posted about this subject on Stack Overflow yesterday[1], but I chose a
> poor example
The + essentially indicates that this is a character-class match. It's to
distinguish things from <.alpha>, , , <-alpha>, and
(among others).
Pm
On Fri, Aug 03, 2018 at 08:48:24PM +0200, Timo Paulssen wrote:
> The + is required, perhaps because the first character after the opening
> < is sup
The + is required, perhaps because the first character after the opening
< is supposed to determine exactly what thing it is? Not sure about
that. The + and - is a bit like "start at nothing, add all alnums, then
subtract all alphas". The + after the < > is just to match it any number
of times, but
That document also says that _ is considered a letter (that is, is matched
by :
https://docs.perl6.org/language/regexes#Predefined_Character_Classes), so
that's the same thing as . I observed that earlier as well.
On Fri, Aug 3, 2018 at 2:37 PM Parrot Raiser <1parr...@gmail.com> wrote:
> If I've
If I've interpreted this
https://docs.perl6.org/language/regexes#Enumerated_character_classes_and_ranges
correctly,
^ is "start of string"
+alnum means "in the alphanumeric set"
-alpha means "not in the purely alphabetic set"
i.e. <+alnum -alpha> means "alphanumeric but not a letter", i.e 0-9_
+
I posted about this subject on Stack Overflow yesterday[1], but I chose a
poor example of something that raises an exception (dividing by zero, which
apparently doesn't necessarily do so) on which the answers have mostly
focused.
I was looking for a way to evaluate an expression, and if the expres
On 08/02/2018 05:18 AM, Timo Paulssen wrote:
Is this what you want?
perl6 -e 'say "12345" ~~ /^<+alnum -alpha>+$/'
｢12345｣
perl6 -e 'say "123a45" ~~ /^<+alnum -alpha>+$/'
Nil
HTH
- Timo
What does the following do?
+alnum (why does it need the "+"?)
-alpha (I presume "-" me
On 08/02/2018 05:18 AM, Timo Paulssen wrote:
Is this what you want?
perl6 -e 'say "12345" ~~ /^<+alnum -alpha>+$/'
｢12345｣
perl6 -e 'say "123a45" ~~ /^<+alnum -alpha>+$/'
Nil
HTH
- Timo
A piece of art. Thank you!
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