How to call a super class method?

Hello fellow perl users, I have been trying to understand perl 6 oop implementation, and one thing I still can't figure out is how to call super class methods from lower classes. Let's say we have two classes, Person and Employee, and the method I am trying to access is the object constructor:

RE: Constants as members of a class

Thanks Liz, I will stick with the method aproach. Regards, Emiliano > Subject: Re: Constants as members of a class > From: l...@dijkmat.nl > Date: Fri, 18 Dec 2015 23:49:53 +0100 > To: perl6-users@perl.org > > > On 18 Dec 2015, at 23:37, TS xx <maringa...@hotmail.com

RE: Constants as members of a class

Hi Liz, thanks for your reply. Can I call the method from static context? I mean: MyClass.FOO > Subject: Re: Constants as members of a class > From: l...@dijkmat.nl > Date: Fri, 18 Dec 2015 10:23:11 +0100 > To: perl6-users@perl.org > > > > On 18 Dec 2015,

RE: Constants as members of a class

that "new" method. Second -- yes, this is a very old interpreter. I unfortunately don't know about the twigil variable constant things. --Brock On Thu, Dec 17, 2015 at 9:46 PM, TS xx <maringa...@hotmail.com> wrote: Hello dear perl6 users, I was in the need of declaring a

Constants as members of a class

Hello dear perl6 users, I was in the need of declaring a member variable as a constant integer. After many syntax tryouts I came to this one: class MyClass { has int $.myConst; method new () { return self.bless(); } submethod BUILD () { constant $!myConst = 1;

Re: Need help with Nil values

Thanks, That was it. Somtimes I get confused with the way other languages treat undefined/null/nil values. Regards, Emiliano From: Timo Paulssen Sent: Tuesday, February 23, 2016 2:20 AM To: perl6-users@perl.org Subject: Re: Need help

pack function

Hi there, I am trying to translate some old perl 5 code and I am having trouble with a particular line. I used to have this in perl 5 to translate multibyte encoding like "%C3%A1": $value =~ s/%([\dA-Fa-f][\dA-Fa-f])/pack("C", hex($1))/eg; And I have translated the regex to something like