Re: Is creating and Array or Parcel ?

2015-08-03 Thread Gabor Szabo
On Mon, Aug 3, 2015 at 3:49 AM, Larry Wall la...@wall.org wrote: On Sun, Aug 02, 2015 at 03:09:07PM +0200, Moritz Lenz wrote: : If you want to extract it from the scalar, use the @ again, this : time as a prefix: : : for @$s { } # two iterations again. Note that this distinction will go

Re: Is creating and Array or Parcel ?

2015-08-03 Thread Timo Paulssen
On 08/02/2015 02:35 PM, Lloyd Fournier wrote: @a = $z[0].list or in a less documented way: @a = $z[0] The idea is that you can store an array in ether a @ or $ variable. Where as in perl5 you could only store a reference in $ variable. The sigil simply tells perl6 how it should behave

Re: Is creating and Array or Parcel ?

2015-08-03 Thread Lloyd Fournier
Non expert opinion here. my $z = ['a', 'b', 'c']; Is a real array. The difference is that is in a non-auto flattening container (variable). If you want to iterate over it you can: for @$z { ... } # like perl5 If you want to assign it to @ array then do the same thing @a = @$z. If you want to

Re: Is creating and Array or Parcel ?

2015-08-03 Thread Richard Hainsworth
Having followed Perl6 from its inception, it is good to see Christmas will be coming this year :) Richard finanalyst On 08/03/2015 08:49 AM, Larry Wall wrote: On Sun, Aug 02, 2015 at 03:09:07PM +0200, Moritz Lenz wrote: : If you want to extract it from the scalar, use the @ again, this : time

Re: Is creating and Array or Parcel ?

2015-08-03 Thread Marc Chantreux
On Sun, Aug 02, 2015 at 10:35:23PM +1000, Lloyd Fournier wrote: If you want to assign to an array which is an element of another array: @a = $z[0].list this is very confusing because this is not a LoL. $z.flat seems more intuitive to me. -- Marc Chantreux (eiro on github and freenode)

Re: Is creating and Array or Parcel ?

2015-08-02 Thread Gabor Szabo
This whole thing sounds quite complex. What is the value behind this complexity? Gabor

Re: Is creating and Array or Parcel ?

2015-08-02 Thread Moritz Lenz
Hi, On 02.08.2015 06:43, Gabor Szabo wrote: On Fri, Jul 31, 2015 at 4:16 PM, Moritz Lenz mor...@faui2k3.org mailto:mor...@faui2k3.org wrote: On 07/31/2015 03:02 PM, Gabor Szabo wrote: The following code (with comments) is confusing me. Can someone give some explanation

Re: Is creating and Array or Parcel ?

2015-08-02 Thread Marc Chantreux
It's an Array inside a Scalar. This is really disturbing from a newcommer perspective. I don't know much about the Perl6 internals so maybe i can explain it better (or someone can fix me): Let's try: Everything is an object in Perl6, which comes with roles and inheritances and

Re: Is creating and Array or Parcel ?

2015-08-02 Thread Larry Wall
On Sun, Aug 02, 2015 at 03:09:07PM +0200, Moritz Lenz wrote: : If you want to extract it from the scalar, use the @ again, this : time as a prefix: : : for @$s { } # two iterations again. Note that this distinction will go away after the Great List Refactor, so Gabor gets his wish. Part of the

Re: Is creating and Array or Parcel ?

2015-08-01 Thread Gabor Szabo
On Fri, Jul 31, 2015 at 4:16 PM, Moritz Lenz mor...@faui2k3.org wrote: On 07/31/2015 03:02 PM, Gabor Szabo wrote: The following code (with comments) is confusing me. Can someone give some explanation please? Specifically the difference between my @x = a b; It's the assignment to the

Re: Is creating and Array or Parcel ?

2015-07-31 Thread Moritz Lenz
On 07/31/2015 03:02 PM, Gabor Szabo wrote: The following code (with comments) is confusing me. Can someone give some explanation please? Specifically the difference between my @x = a b; It's the assignment to the Array variable that makes the Array here; by itself just creates a Parcel:

Is creating and Array or Parcel ?

2015-07-31 Thread Gabor Szabo
The following code (with comments) is confusing me. Can someone give some explanation please? Specifically the difference between my @x = a b; my $z = @x; and my $z = a b; Gabor use v6; # creates an array here: my @x = a b; say @x.WHICH; # Array|140713422866208 say @x;# a b say