On Mon, Aug 3, 2015 at 3:49 AM, Larry Wall wrote:
> On Sun, Aug 02, 2015 at 03:09:07PM +0200, Moritz Lenz wrote:
> : If you want to extract it from the scalar, use the @ again, this
> : time as a prefix:
> :
> : for @$s { } # two iterations again.
>
> Note that this distinction will go away after
Hi,
I there a way to prevent some type of mistake I now have made several
times merely because the error messages are not helping me to point to
the problem.
Example;
grammar Turtle::Grammar {
rule TOP { * }
...
rule directive { | }
...
rule base {
'@base'*
Non expert opinion here.
my $z = ['a', 'b', 'c'];
Is a real array. The difference is that is in a non-auto flattening
container (variable). If you want to iterate over it you can:
for @$z { ... } # like perl5
If you want to assign it to @ array then do the same thing @a = @$z.
If you want to a
Having followed Perl6 from its inception, it is good to see Christmas
will be coming this year :)
Richard
On 08/03/2015 08:49 AM, Larry Wall wrote:
On Sun, Aug 02, 2015 at 03:09:07PM +0200, Moritz Lenz wrote:
: If you want to extract it from the scalar, use the @ again, this
: time as a prefi
On Sun, Aug 02, 2015 at 10:35:23PM +1000, Lloyd Fournier wrote:
> If you want to assign to an array which is an element of another array:
>
> @a = $z[0].list
this is very confusing because this is not a LoL. $z.flat seems more
intuitive to me.
--
Marc Chantreux (eiro on github and freenode)
htt
I think actually belongs under the "LTA error message" category.
On 8/3/15, mt1957 wrote:
> Hi,
>
> I there a way to prevent some type of mistake I now have made several
> times merely because the error messages are not helping me to point to
> the problem.
>
> Example;
>
>grammar Turtle::Gra
On 08/02/2015 02:35 PM, Lloyd Fournier wrote:
> @a = $z[0].list
>
> or in a less documented way:
>
> @a = $z[0]<>
>
> The idea is that you can store an array in ether a @ or $ variable.
> Where as in perl5 you could only store a reference in $ variable. The
> sigil simply tells perl6 how it shoul
