On Wed, Dec 19, 2018 at 7:58 AM ToddAndMargo via perl6-users <
perl6-users@perl.org> wrote:
> In the mean time, I will ue
if $x.contains("b") && not $x.contains( "q" )
> On 12/18/18 4:13 PM, Ralph Mellor wrote, demonstrating he never misses
> anything:
> > $x.contains("b") && not
On Tue, Dec 18, 2018 at 10:49 PM ToddAndMargo via perl6-users
mailto:perl6-users@perl.org>> wrote:
Hi All,
Where is my booboo?
$ p6 'my$x="abcd"; if $x.contains("b" && not "q") {say "y"}else{say
"n"};'
n
In the mean time, I will ue
if $x.contains("b") &&
.contains tests whether its invocant, treated as a string, contains its
argument, treated as a string.
The argument you've given to .contains is:
"b" && not "q".
That's not a string.
Here's one option:
my$x="abcd"; if $x.contains("b") && not $x.contains("q") {say "y"}else{say
"n"};
On Tue,
