Michael Glaesemann wrote:
On Sep 25, 2007, at 17:30 , Alvaro Herrera wrote:
Michael Glaesemann wrote:
select dom_id,
dom_name,
usr_count
from domains
natural join (select usr_dom_id as dom_id,
count(usr_dom_id) as usr_count
from
Madison Kelly wrote:
Thanks for your reply!
Unfortunately, in both cases I get the error:
nmc= SELECT dom_id, dom_name, COUNT(usr_dom_id) AS usr_count FROM domains
JOIN users ON (usr_dom_id=dom_id) HAVING COUNT (usr_dom_id) 0 ORDER BY
dom_name;
ERROR: syntax error at or near COUNT
Madison Kelly [EMAIL PROTECTED] writes:
SELECT d.dom_id, d.dom_name FROM domains d WHERE (SELECT COUNT(*) FROM users u
WHERE u.usr_dom_id=d.dom_id) 0 ORDER BY d.dom_name ASC;
Which gives me just the domains with at least one user under them, but not
the count. This is not ideal, and I
On Sep 26, 2007, at 7:41 , Madison Kelly wrote:
Unfortunately, in both cases I get the error:
Um, the two cases could not be giving the same error as they don't
both contain the syntax that the error is complaining about: the
first case uses count in a subquery so it couldn't throw
Gregory Stark wrote:
Madison Kelly [EMAIL PROTECTED] writes:
SELECT d.dom_id, d.dom_name FROM domains d WHERE (SELECT COUNT(*) FROM users u
WHERE u.usr_dom_id=d.dom_id) 0 ORDER BY d.dom_name ASC;
Which gives me just the domains with at least one user under them, but not
the count. This is
Hi all,
I've read 7.2.1.3 (as short as it is) in the PgSQL docs, but don't
see what I am doing wrong... Maybe you can help?
I've got a query;
SELECT
d.dom_id,
d.dom_name,
(SELECT COUNT(*) FROM users u WHERE u.usr_dom_id=d.dom_id)
AS
usr_count
FROM
On Sep 25, 2007, at 16:59 , Madison Kelly wrote:
SELECT
d.dom_id,
d.dom_name,
(SELECT COUNT(*) FROM users u WHERE u.usr_dom_id=d.dom_id)
AS
usr_count
FROM
domains d
WHERE
(SELECT COUNT(*) FROM users u WHERE u.usr_dom_id=d.dom_id) 0
ORDER
Michael Glaesemann wrote:
On Sep 25, 2007, at 16:59 , Madison Kelly wrote:
SELECT
d.dom_id,
d.dom_name,
(SELECT COUNT(*) FROM users u WHERE u.usr_dom_id=d.dom_id)
AS
usr_count
FROM
domains d
WHERE
(SELECT COUNT(*) FROM users u WHERE
On Sep 25, 2007, at 17:30 , Alvaro Herrera wrote:
Michael Glaesemann wrote:
select dom_id,
dom_name,
usr_count
from domains
natural join (select usr_dom_id as dom_id,
count(usr_dom_id) as usr_count
from users) u
where usr_count 0
Michael Glaesemann [EMAIL PROTECTED] writes:
I believe you'd have to write it like
select dom_id, dom_name, count(usr_dom_id) as usr_count
from domains
join users on (usr_dom_id = dom_id)
having count(usr_dom_id) 0
order by dom_name;
I don't know how the performance would
On Sep 25, 2007, at 21:44 , Tom Lane wrote:
... which in English means we just do the calculation once ...
As always, thanks, Tom, for the explanation (and Alvaro, who probably
already knew this :))
Michael Glaesemann
grzm seespotcode net
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