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On Thu, Aug 18, 2016 at 3:03 PM, wrote:
> Hi Francisco,
> thanks a lot. I will
On Thu, Aug 18, 2016 at 4:56 AM, wrote:
> select custid, count(vendid) as c415 from cv where vendid = 415 group by
> custid
> [...]
>
> Is there a better way (by creating an aggregate function, perhaps)
>
You may find crosstab in the tablefuncs extension to be of use.
Hello.
On 18.8.2016 10:56, haman...@t-online.de wrote:
>
> Hi,
>
> I have a table cv with custid and vendid columns. Every entry represents the
> purchase of a product
> available from a specific vendor.
> Now, for a set of "interesting" vendors, I would like to select a new table
> custid,
On Thu, Aug 18, 2016 at 10:56 AM, wrote:
> I have a table cv with custid and vendid columns. Every entry represents the
> purchase of a product
> available from a specific vendor.
> Now, for a set of "interesting" vendors, I would like to select a new table
> custid, c415,