Re: [PERFORM] difference in plan between 8.0 and 8.1?

2005-08-26 Thread Alan Stange
Tom Lane wrote: Alan Stange <[EMAIL PROTECTED]> writes: Unique (cost=2717137.08..2771407.21 rows=10854026 width=8) -> Sort (cost=2717137.08..2744272.14 rows=10854026 width=8) Sort Key: timeseriesid -> Bitmap Heap Scan on tbltimeseries (cost=48714.09..1331000.42 row

Re: [PERFORM] difference in plan between 8.0 and 8.1?

2005-08-26 Thread Merlin Moncure
> Hello all, > > I was hoping someone could explain the plan for a statement. > > We have a table with a column of longs being used as an index. The > query plan in 8.0 was like this: > > # explain select distinct timeseriesid from tbltimeseries where > timeseriesid > 0 order by timeseriesid;

Re: [PERFORM] difference in plan between 8.0 and 8.1?

2005-08-26 Thread Tom Lane
Alan Stange <[EMAIL PROTECTED]> writes: > Unique (cost=2717137.08..2771407.21 rows=10854026 width=8) >-> Sort (cost=2717137.08..2744272.14 rows=10854026 width=8) > Sort Key: timeseriesid > -> Bitmap Heap Scan on tbltimeseries > (cost=48714.09..1331000.42 rows=10854026 w

Re: [PERFORM] difference in plan between 8.0 and 8.1?

2005-08-26 Thread Michael Fuhr
On Fri, Aug 26, 2005 at 10:45:07AM -0400, Alan Stange wrote: > -> Bitmap Heap Scan on tbltimeseries (cost=48714.09..1331000.42 > rows=10854026 width=8) > Recheck Cond: (timeseriesid > 0) > -> Bitmap Index Scan on idx_timeseris (cost=0.00..48714.09 > rows=1085

[PERFORM] difference in plan between 8.0 and 8.1?

2005-08-26 Thread Alan Stange
Hello all, I was hoping someone could explain the plan for a statement. We have a table with a column of longs being used as an index. The query plan in 8.0 was like this: # explain select distinct timeseriesid from tbltimeseries where timeseriesid > 0 order by timeseriesid; SET