Hello,
Le 2/07/09 23:21, Greg Stark a écrit :
On Thu, Jul 2, 2009 at 3:48 PM, Jasmin
Dizdarevic wrote:
customer ; seg
111 ; L1
111 ; L2
111 ; L1
222 ; L3
222 ; L3
222 ; L2
the result should look like this:
111: L1 - because L1 is higher than L2 and ratio of L1 : L2 is 2 : 1
222: L3 - because
On Thu, Jul 2, 2009 at 3:48 PM, Jasmin
Dizdarevic wrote:
> customer ; seg
> 111 ; L1
> 111 ; L2
> 111 ; L1
> 222 ; L3
> 222 ; L3
> 222 ; L2
>
> the result should look like this:
>
> 111: L1 - because L1 is higher than L2 and ratio of L1 : L2 is 2 : 1
> 222: L3 - because L3 is higher than L2 and rat
Jasmin Dizdarevic wrote:
hi,
i have to create a aggregate function which evaluates a maximum text
value but with some conditions i have to take care of.
is there a way to access a value set of each group?
e.g.:
customer ; seg
111 ; L1
111 ; L2
111 ; L1
222 ; L3
222 ; L3
222 ; L2
the res
hi,
i have to create a aggregate function which evaluates a maximum text
value but with some conditions i have to take care of.
is there a way to access a value set of each group?
e.g.:
customer ; seg
111 ; L1
111 ; L2
111 ; L1
222 ; L3
222 ; L3
222 ; L2
the result should look like this:
111:
Cool thanks then not something I'm doing wrong :). Is this going to be
changed or is changed in a latter version of postgres. (Do I need to do
and upgrade or write a work around :) )
Tom Lane wrote:
Tim Haak writes:
I am running the following query again a partitioned table in 8.2.7. It
d
