Re: [SQL] Selecting latest value II

2001-09-27 Thread Carl van Tast
Hi, Thurstan On Thu, 20 Sep 2001 17:30:46 +0100, "Thurstan R. McDougle" <[EMAIL PROTECTED]> wrote: > [...] >Carl van Tast had 2 good methods as follows > >SELECT userid, val >FROM tbl >WHERE NOT EXISTS (SELECT * FROM tbl AS t2 > WHERE tb

Re: [SQL] Subquery with IN or EXISTS

2001-09-26 Thread Carl van Tast
this before? ;-)) You might try: SELECT tab.* FROM tab, tab2 WHERE tab.col1 = tab2.col2; or SELECT DISTINCT ... , if col2 is not unique in tab2. Kind regards, Carl van Tast ---(end of broadcast)--- TIP 3: if posting/reading through Usenet,

Re: [SQL] Query does not work: parse ERROR, Re: How to enter lists into database: Problems with solution.

2001-09-26 Thread Carl van Tast
e_id = matches.people_id AND matches.match_count = searched.attribute_count; and it seems to work now. >Thank you very much, >Frederick HTH, Carl van Tast ---(end of broadcast)--- TIP 6: Have you searched our list archives? http://archives.postgresql.org

Re: [SQL] group by weirdness

2001-09-19 Thread Carl van Tast
ml WHERE state IN (2, 5) GROUP BY jid) ml2 ON (j.id = ml2.jid) WHERE j.fkey = 1; HTH, Carl van Tast ---(end of broadcast)--- TIP 5: Have you checked our extensive FAQ? http://www.postgresql.org/users-lounge/docs/faq.html

Re: [SQL] group by weirdness

2001-09-17 Thread Carl van Tast
ml1 ON (j.id = ml1.jid) LEFT JOIN (SELECT jid, COUNT(*) cnt FROM ml WHERE state IN (2, 5) GROUP BY jid) ml2 ON (j.id = ml2.jid) WHERE j.fkey = 1; HTH, Carl van Tast On Tue, 11 Sep 2001 02:26:32 + (UTC), [EMAIL PROTECTED] (Joseph Shraibman) wrote: &g

Re: [SQL] default value syntax - pg compared to?

2001-03-12 Thread Carl van Tast
x27;c') set identity_insert foo off insert into foo (txt) values ('b') select * from foo id txt --- -- 1 a 2 b 10 c 11 d (4 row(s) affected) .02 by Carl van Tast ---(end of broadcast)--