I've never used functions in postgres, but the line
*resultp = *testo;
looks wrong to me. Shouldn't it be
strcpy(resultp, testo);
?
Regards,
Patrik Kudo
ech`echo xiun|tr nu oc|sed 'sx\([sx]\)\([xoi]\)xo un\2\1 is xg'`ol
Känns det oklart? Fråga på!
On Thu, 12 Jul 2001, Fernando Eduardo B.
#include
#include
char *fernando(char *texto)
{
char *resultp = palloc(strlen(texto)+5);
*resultp = *texto;
strcat(resultp," mais");
return resultp;
}
gcc -shared fernando.c -o fernando.so
CREATE FUNCTION fernando (bpchar) RETURNS bpchar
AS '/u/src/tef/fer
Forest Wilkinson <[EMAIL PROTECTED]> writes:
> That's an int8 meaning "eight bit integer". I want to work with an int8
> meaning "64 bit integer", as described in the docs:
> http://www.postgresql.org/users-lounge/docs/7.0/user/datatype.htm#AEN942
> So how do I return one of these suckers from a
That's an int8 meaning "eight bit integer". I want to work with an int8
meaning "64 bit integer", as described in the docs:
http://www.postgresql.org/users-lounge/docs/7.0/user/datatype.htm#AEN942
So how do I return one of these suckers from a C function?
Forest
On Thu, 21 Sep 2000 10:32:50 +0
On Thu, 21 Sep 2000, Forest Wilkinson wrote:
> I have written a few Postgres extension functions in C, and want to modify
> some of them to return an int8. However, I don't see any int8 definition
> in postgres.h. (I have the 7.0.2 RPMs installed.) How should I
> accomplish this?
in the sou
I have written a few Postgres extension functions in C, and want to modify
some of them to return an int8. However, I don't see any int8 definition
in postgres.h. (I have the 7.0.2 RPMs installed.) How should I
accomplish this?
