I have the same problem as you when using apache1.3.19, php4.0.5 and
mysql3.23.38 and get the same warning message. I've spent many time to
compile
the system again but failed. So I forgive to use the newest version and use
apache1.3.17, php4.0.4 and mysql3.23.38. It works now!
Hope someone can
Try putting the variable into single quotes
mysql_db_query(phpads, DELETE FROM adviews WHERE
bannerID='$banresult[bannerID]');
That should resolve the problem.
Sincerely,
Craig Vincent
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For
Alan Hale wrote:
http://www.devshed.com/Server_Side/MySQL/JS_Arrays/
I found it difficult to understand what was going on because the code
example is embedded in the rest of a complex page layout. I also think there
are errors in the code, which I've only partly sorted out (I'm a Javascript
Hi all
I come out of a client/server environment and am wanting to learn
Web-programming - Specifically PHP.
I am using Windows Me, Apache as my web server, Interbase as my Database and
php-4.0.3pl1-installer.exe.
My question:
Are there any installation guides for this type of set-up? (I have