Closest you might get is
if ( mysql_result($result,0,3 ) == 'foo') {
$user = $mysql_fetch_row($result);
}
bastien
From: Stut <[EMAIL PROTECTED]>
To: Peter Beckman <[EMAIL PROTECTED]>
CC: PHP-DB Mailing List
Subject: Re: [PHP-DB] Direct Access to an Array Item?
Date: Thu, 10 Aug 2006 0
On 8/9/06, Peter Beckman <[EMAIL PROTECTED]> wrote:
I want to access a variable within a function-returned array without
setting the array to a variable first. Example -- test for equal to
string
'foo' on the 4th element of a returned fetch row:
if (($row = mysql_fetch_row($result))[3] ==
Peter Beckman wrote:
> if (($row = mysql_fetch_row($result))[3] == 'foo') {
> $user = $row;
> }
>
> or
>
> $bar = explode('#', $str)[2];
PHP does not currently support this type of syntax in any form. You must
assign the return value of a function to a variable if you want to
On 8/9/06, Peter Beckman <[EMAIL PROTECTED]> wrote:
I want to access a variable within a function-returned array without
setting the array to a variable first. Example -- test for equal to
string
'foo' on the 4th element of a returned fetch row:
if (($row = mysql_fetch_row($result))[3] ==
On Wed, 9 Aug 2006, Bastien Koert wrote:
use mysql_result
mysql_result ( $result, 0, 2 )
where 2 is the offset of the fields in the row
In one line of code, I want to fetch the row into a variable, and test a
variable within that row.
I want to know how to do this both within a DB query
use mysql_result
mysql_result ( $result, 0, 2 )
where 2 is the offset of the fields in the row
Bastien
From: Peter Beckman <[EMAIL PROTECTED]>
To: PHP-DB Mailing List
Subject: [PHP-DB] Direct Access to an Array Item?
Date: Tue, 8 Aug 2006 22:34:55 -0400 (EDT)
I want to access a variable w
Try the MSDN library:
http://msdn.microsoft.com/library/default.asp?url=/library/en-us/ado270/htm/mdobjconnectionpme.asp
- Frank
> Chris wrote:
> > Todd Cary wrote:
> >> [Sorry - I misposted this in the General group]
> >>
> >> I am in the process of converting my clients PHP scripts that are
>
