Hi
is the syntax error reported for the php or the SQL? Better yet,
supply the actual error message, so we can see for ourselves
Niel
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JD wrote:
Can anyone help me figure out what is wrong with this syntax. Thanks.
list($qh,$num) = dbQuery("SELECT password AS passwd1,
$DATABASE_PASSWORD_FUNCTION('$password') AS passwd2 ".
"FROM $USER_TABLE WHERE username='$username'");
$data = dbResult($qh);
No need to repost your quest
Can anyone help me figure out what is wrong with this syntax. Thanks.
list($qh,$num) = dbQuery("SELECT password AS passwd1,
$DATABASE_PASSWORD_FUNCTION('$password') AS passwd2 ".
"FROM $USER_TABLE WHERE username='$username'");
$data = dbResult($qh);
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PHP Database Mailing List (http://www.p
I am getting a syntax error in the statement below. Can anyone tell me what
it is. Thanks.
list($qh,$num) = dbQuery("SELECT password AS passwd1,
$DATABASE_PASSWORD_FUNCTION('$password') AS passwd2 ".
"FROM $USER_TABLE WHERE username='$username'");
$data = dbResult($qh);
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PHP Database Mai
[EMAIL PROTECTED] wrote:
- Original Message - From: "chris smith" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Cc:
Sent: Friday, January 05, 2007 12:08 PM
Subject: Re: [PHP-DB] CURL and process not finishing
On 1/5/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
I am using CURL to ch
Hi
You have two functions between the if and else, the syntax you've used
only allows one. Use braces.
if(mysql_query($sql)) {
mail ($email, "Thank you for registering!", $body, "From:
[EMAIL PROTECTED]");
header("Location: thankYou.php");
} else {
die("Error! Could not insert values".m
Hi,
I am trying to send an email to the user after he registers himself on the
website. The code is a DB code that
1) Inserts the data to DB table
2) Sends an email to the user with his details.
3) Passes on a Thank you page.
The code works fine without the email code. But I get this error when
