how about like this:
echo "\n";
$result = @mysql_query("SELECT image FROM specials");
while($row = mysql_fetch_row($result)) {
echo "\n";
}
echo "\n\n";
hope it helps!
matt
On Jan 5, 2008 4:51 PM, Thomas <[EMAIL PROTECTED]> wrote:
> I'm attempting to make a table with one row and 3 columns h
I'm attempting to make a table with one row and 3 columns holding three
different images. I want each image URL to be called from my database.
Everything is set-up in my database. When I use the following code, it
places the same picture across the three columns and does this three times
(c