Ron Piggott wrote:
When I do the following command:
$number_of_entries=mysql_numrows($blog_activity_result);
and there are no rows I get an error (Warning: mysql_numrows(): supplied
argument is not a valid MySQL result resource in ...)
Fix the error from $blog_activity_result as someone else
query in error $blog_activity_result ,
$number_of_entries=mysql_numrows($blog_activity_result);
this line before
echo mysql_error();
add , you see error . after edit your error :))
2008/10/12, Roberto Carlos García Luís <[EMAIL PROTECTED]>:
> You can use, [EMAIL PROTECTED]($blog_activity_result);
You can use, [EMAIL PROTECTED]($blog_activity_result);
with @ you silence the error in the display.
Robert C.
El 12/10/2008, a las 01:19 p.m., Ron Piggott escribió:
When I do the following command:
$number_of_entries=mysql_numrows($blog_activity_result);
and there are no rows I get an erro
When I do the following command:
$number_of_entries=mysql_numrows($blog_activity_result);
and there are no rows I get an error (Warning: mysql_numrows(): supplied
argument is not a valid MySQL result resource in ...)
When that happens I want to display a greeting to invite the user to
engage in
On Sun, Oct 12, 2008 at 6:10 AM, Velen <[EMAIL PROTECTED]> wrote:
> Hi
>
> I have 3 frames on my index page using frameset. I want to display another
> content in the other frames when a user has logged in successfully.
>
> My code is like that:
>
> ## if user exists and have corresponding passwo
Hi
I have 3 frames on my index page using frameset. I want to display another
content in the other frames when a user has logged in successfully.
My code is like that:
## if user exists and have corresponding password mysql_num_rows >0
if(mysql_num_rows($res) != 0) {
x code to dis
