Dear Gary
$_SESSION variable would be available only if you have session_start() at
the top of the page. For $_POST, i presume u hve method POST defined for the
form element
============
regds
amit
"The difference between fiction and reality? Fiction has to make sense."
On Mon, Feb 21, 2011 at 10:39 PM, Gary <gp...@paulgdesigns.com> wrote:
> I have a 3 step form that calls the data from a mysql DB. First is a
> dropdown to select a state, which then brings up a dynamically created
> check
> list of the counties in that state, so far all works well. I am unable to
> get the checkbox choices to appear on the third page.
>
> If someone could take a look at this and tell me where I am going wrong.
>
> This is the code for the page that creates the checkboxes. There are some
> extra lines in there where I was trying to get it to work. Again this works
> fine, but my guess is that see this may shed light.
>
> <?php
> $county1=$_SESSION['county$i'];
> $counties=$_SESSION['counties'];
> $row_name=$_SESSION['name'] = $row[name];
> $count_choice=$_SESSION['name'];
> $result1=$_SESSION['$result'];
> $choice=$_POST['state'];
> if ( isset($_POST['submit']) ) { // if form is submitted, process it
>
> for($i=1; $i<=$_POST['counties']; $i++) {
> if ( isset($_POST["county$i"] ) ) {
> print $_POST["county$i"]." is checked.<br/>";
> }
> }
>
> } else { // if form isn't submitted, output the form
> $county_choice=$_SESSION['county$1'];
> print "<form action=\"phpForm3.php\" method=\"POST\">\n";
>
> /*$link = mysql_connect("", "", "");
> mysql_select_db("");*/
> $result = mysql_query("SELECT * FROM `counties` WHERE state_id =
> '$choice'")
> or die(mysql_error());
>
> if ($result) {
> print "<table width=200 border=1>\n";
>
> print "<th> </th>\n";
> print "<th> State </th>\n"; //2 fields in Counties table, State and County
> print "<th> County </th>\n";
>
> print "</tr>\n";
> //create table
> $i = 0;
> while ( $row = mysql_fetch_array($result) ) {
> $i++;
> print "<tr>\n";
>
> print "<td><input type=\"checkbox\" name=\"county$i\"
> value=\"$row[name]\"></td>\n";
>
> echo "<td>{$row['state_id']}</td>\n";
>
> echo "<td>{$row['name']}</td>\n";
>
> echo "</tr>\n";
>
> }//end while
> print "</table>\n";
> } else {
> echo("<P>Error performing query: " .
> mysql_error() . "</P>");
>
> }
> print "<input type=\"hidden\" name=\"counties\" value=\"$i\"/>\n";
> print "<input type=\"submit\" name=\"submit\" value=\"Go\"/>\n";
> }
>
>
> This is the page that I am unable to get to call the checkbox selections
>
> <?php
> $count_choice1=$_SESSION['county$i'];
> $count_choice2=$POST['counties'];
> $count_choice3=$_POST['name'];
> $result1=$_SESSION['$result'];
> /*$count_choice=$_SESSION['name']; */
> $count_choice=$_POST['county$i'];
> $choice=$_SESSION['name'];
> $_POST["county$i"];
>
>
> $result = mysql_query("SELECT * FROM `counties` WHERE name = '$choice'") or
> die(mysql_error());
> /*$query = mysql_query("SELECT * FROM counties ");
> $result = mysql_query($query) or die ("Error in query: $query.
> ".mysql_error());;
> echo $row['name'];
> echo "$query";*/
> while($row = mysql_fetch_array($result))
> {
> echo $row['name'];
> /*"{$row['name']}<br>" ;*/
>
>
> }
> echo "$choice";
> /*echo $_SESSION['county$i'];
> echo $_SESSION['counties'];
> echo $_SESSION['name'];
> echo "$count_choice";
> echo "$row['name']";
> echo "$county$1";
> echo "$counties";
> echo "$row_name"; */
> ?>
> --
>
> Any Suggestions?
>
> Thank you.
>
>
> Gary
>
>
>
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